Dont solve integrals individually

Calculus Level 5

If the integral 0 1 ln 3 ( 1 x ) ln 2 ( x ) 1 x d x 3 0 1 ln ( 1 x ) Li 2 2 ( 1 x ) 1 x d x = a ζ b ( c ) d ζ ( a ) \int_0^1\frac{\ln^3(1-x)\ln^2(x)}{1-x}dx-3\int_0^1\frac{\ln(1-x)\operatorname{Li}_2^2(1-x)}{1-x}dx=a\zeta^b(c)-d\zeta(a) where a , b , c , d a,b,c,d are positive integers and b , c b,c are distinct primes. Find a + b + c + d a+b+c+d .

Notation: Li 2 ( x ) \operatorname{Li}_2(x) is dilogarithm function and ζ ( z ) \zeta(z) is Riemann zeta function .

Calculating each individual integrals make work lengthy so best way to evaluate one integral that cancels another .

This is an original and proposed issue .


The answer is 19.

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