x and y are integers where x 2 + y 2 = 1 0 0 0 0 0 . What is the sum of all possible values of x and y?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Please update your solution accordingly.
12^2 + 316^2 = 100000
100^2 + 300^2 = 100000
180^2 + 260^2 = 100000
But, why this solution is 0 ?
The 'don't think so hard' reference in the title meant that you can simply divide both sides of the equation by 1 0 0 0 0 = 1 0 0 2 and create additional variables t = 1 0 0 x and z = 1 0 0 y ,. We now have t 2 + z 2 = 1 0 . It's clear that 1 and 9 are the only perfect squares adding up to 1 0 , hence { x = ± 1 0 0 y = ± 3 0 0 or { x = ± 3 0 0 y = ± 1 0 0 .
Log in to reply
U can't get the solution this way.
Even 260²+180²=100000
Its just the ± effect which makes the answer 0
Problem Loading...
Note Loading...
Set Loading...
For every positive solution of p and q, there will be a corresponding negative value. All the values will negate and the answer will be 0.