dont think so hard

x and y are integers where x 2 + y 2 = 100000. x^2+y^2=100000. What is the sum of all possible values of x and y?


The answer is 0.

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1 solution

Trevor Arashiro
Jun 20, 2014

For every positive solution of p and q, there will be a corresponding negative value. All the values will negate and the answer will be 0.

Please update your solution accordingly.

Calvin Lin Staff - 6 years, 11 months ago

12^2 + 316^2 = 100000

100^2 + 300^2 = 100000

180^2 + 260^2 = 100000

But, why this solution is 0 ?

Shohag Hossen - 6 years ago

The 'don't think so hard' reference in the title meant that you can simply divide both sides of the equation by 10000 = 10 0 2 10000=100^2 and create additional variables t = x 100 t=\frac{x}{100} and z = y 100 z=\frac{y}{100} ,. We now have t 2 + z 2 = 10 t^2+z^2=10 . It's clear that 1 1 and 9 9 are the only perfect squares adding up to 10 10 , hence { x = ± 100 y = ± 300 \begin {cases}x=\pm 100\\y=\pm 300\end{cases} or { x = ± 300 y = ± 100 \begin {cases}x=\pm 300\\y=\pm 100\end{cases} .

mathh mathh - 6 years, 11 months ago

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U can't get the solution this way.

Even 260²+180²=100000

Its just the ± effect which makes the answer 0

Rohit Sachdeva - 6 years, 8 months ago

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And 30 0 2 + 10 0 2 300^{2}+100^{2} !

Bryan Lee Shi Yang - 6 years, 1 month ago

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