Doppler's Effect

Classical Mechanics Level 3

A source emitting a sound frequency v v is placed at a large distance from an observer. The source starts moving towards the observer with a uniform acceleration a a . Find the frequency heard by the observer corresponding to the wave emitted just after the source starts. The speed of sound in air is u u .

Details And Assumptions :

v = 500 Hz , a = 10000 m/s 2 , u = 340 m/s v=500 \text{ Hz} , a= 10000 \text{ m/s}^2 , u=340 \text{ m/s} .


The answer is 515.1515.

Nikhil Tanwar by Nikhil Tanwar , 24, India

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1 solution

Aryan Goyat
May 29, 2016

ok this one was nice what you need is actually the proof of doppler's effect

let the wavelength(original) be lambda.so time =lamda/u

distance travelled by the source =1a(lamda/u)^(2)/2

new lamda=lamda-1a(lamda/u)^(2)/2

new frequency=u/new lamda

use (original lamda)=u(old frequency)

1 Helpful 0 Interesting 0 Brilliant 0 Confused

absolutely @aryan goyat , one must recall the way of proving , most of cases of doppler's effect ..

Rudraksh Sisodia - 4 years, 9 months ago

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