Dot Dot Dot and Many Dots.

On each row, the first two tiles are operands and last tile is the result. The result is calculated in the following manner: Each dot in first operand is combined with a dot in the same location in the second operand. The resulting dot is placed in the same location in the result tile. Combination results are as follows, operations are commutative (operands order doesn't matter):

• White and black produce blank space (no dot).
• White and blank space (no dot) produce blank space (no dot)
• Black and blank space (no dot) produce blank space (no dot).
• White and white produce black.
• Black and black produce white.

Hence the correct answer is G (White dot in top left position and black dot in bottom left position).

I think my way is easier to understand. In each row and column the third square is the result of operations on first and second square.

Step 1: $A\bigcap B$ (While taking intersection the color of the dot must be considered. We won't take two dots with different color and same position in the intersection)

Step 2: Reverse the colors. The black dots become white and white become black.

Finally you'll get the answer.

Following are the rules followed:-

• Two Black Dots Combine To Make A White Dot
• Two White Dots Combine To Make A Black Dot
• One Black Dot And One White Dot Combine To Make A Blank
• A Blank Combined With Anything Makes A Blank

In the last row, the two black dots will combine to form a white dot in the top-left corner.

In the middle of the square, a blank combines with a black dot. This will result in a blank.

Hence the answer is square G .