Double Chord

Geometry Level 3

In the diagram, the two concentric circles have radii 18 18 and 20. 20.

A D \overline{AD} is a chord of the larger circle that intersects the smaller at points B B and C . C.

Find A B × B D . AB\times BD.


The answer is 76.

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2 solutions

Relevant wiki: Power of a Point

Let E F EF be a diameter of the larger circle that passes through B B .

Note that by Power of a Point,

A B × B D = E B × B F AB \times BD = EB \times BF and E B = 20 18 ; B F = 20 + 18 EB = 20 - 18; BF = 20 + 18 .

So A B × B D = E B × B F = ( 38 ) ( 2 ) = 76 AB \times BD = EB \times BF = (38)(2) = \boxed{76} .

Jeremy Galvagni
Jun 9, 2018

Q C 2 = 1 8 2 O Q 2 QC^{2}=18^{2}-OQ^{2}

Q A 2 = 2 0 2 O Q 2 QA^{2}=20^{2}-OQ^{2}

A B = Q A Q C AB = QA - QC

B D = Q C + Q A BD = QC + QA

A B B D = ( Q A Q C ) ( Q A + Q C ) = Q A 2 Q C 2 AB\cdot BD = (QA-QC)(QA+QC) = QA^{2} - QC^{2}

= ( 2 0 2 O Q 2 ) ( 1 8 2 O Q 2 ) = (20^{2} - OQ^{2}) - (18^{2} - OQ^{2})

= 2 0 2 1 8 2 = ( 20 + 18 ) ( 20 18 ) = 38 2 = 76 = 20^{2} - 18^{2} = (20+18)(20-18) = 38\cdot 2 = \boxed{76}

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