Double delight with 1729!!

Calculus Level 5

1729 1729 14 π 14 π ( 4 cos ( y ) + sin 2 ( x ) + 2 x y ) d y d x \int_{-1729}^{1729} \int_{-14\pi}^{14\pi} (4\cos (y)+\sin^2 (x) + 2xy) \ dy \ dx

Evaluate the above double integral. Round up your answer to the nearest integer.


The answer is 152057.

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1 solution

Peter Macgregor
Feb 19, 2015

Consider the inner integral first.

The 4 cos y 4\cos{y} contributes zero because it is integrated over an integer multiple of its period.

The 2 x y 2xy contributes zero because y y is an odd function, and it is integrated over an interval centred on the origin.

Integrating the remaining term is easy because as far as the inner integral is concerned it is a constant.

Making use of these observations the double integral simplifies to

1729 1729 28 π sin 2 x d x \int_{-1729}^{1729} 28\pi\sin^2{x} \ dx

Transform this into an integrable form with a trig. identity to get

14 π 1729 1729 1 cos 2 x d x 14\pi\int_{-1729}^{1729}1-\cos{2x}\ dx

Now everyday integration gives, to the nearest integer, the answer 152057 \boxed{152057}

In the last step how did limits change from 1729 to 1792 In question its given 1729

Akhil D - 4 years, 7 months ago

Log in to reply

sorry, it is a typo. I'll edit my solution.

Peter Macgregor - 4 years, 7 months ago

And I got answer as 152118 after rounding off

Akhil D - 4 years, 7 months ago

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