Double transformation

Let $v=2\hat{i}-3\hat{j}$ . If the basis vectors $\hat{i}$ and $\hat{j}$ swap positions, and then $\hat{i}$ 's length doubles, while $\hat{j}$ rotates $\frac{\pi}{4}$ radians anticlockwise and triples its length, what is the new vector ${v}$ ? If this is equal to the vector $\begin{pmatrix} a\sqrt{b} \\ a\sqrt{b}-c \end{pmatrix}$ , find $a+b+c$ .

Note: I don't know how to put an arrow above the v so can someone do it for me thanks.