A ping-pong ball fell into a narrow pipe metal pipe, one foot deep, embedded in concrete. How would you get it out undamaged?
You have:
1. Ping Pong Paddle
2. Shoe Laces
3. A Bottle Full Of Water
4. A Hammer
With which one could you take the ball out easily?
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If the ball hits a switch in the pipe permanently deactivating the artificial gravity field on your space ship, you are screwed.
Why would I keep the switch to my space-ship's angular momentum-based artificial gravity inside a random pipe? And why would I have said pipe embedded in concrete?
Yeah the rest of the solutions are pretty good but what if the ball's diameter leaves no space for the water to go underneath it?
The ball must have a smaller diameter than the pipe, only then it might have been stuck in it, Otherwise there wouldn't be a problem.
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I reread the question. Seems like I earlier thought that the pipe was bottomless, and therefore deduced that the ball got stuck somewhere in between due to structural inconsistencies in the pipe. Thanks for correcting the fallacy in my statement.
Exactly my freind you are right .
On poring the water into the metal pipe the ball will start to float which then gradually rises near the surface of the pipe. Then we could easily pick the ball without getting it damaged at all. And thus the correct answer is option (3).
the ball is lighter than the water, so it will float when water is poured into the hole
Make the ball float using the water.
Ping Pong balls float.. the end
because in these options ''A Bottle Full of Water'' is the only solution. only water can prevent from damages. Archimedes's principle .The ball then according to his rule will start floating
by archimedes's principle the answer is a bottle full of waterr.............:)
The rule of buoyancy states that a light object,when with water, floats - so you could get the ball already once you fill in thewater.
An iron filling is light. Why does it not float?
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It's because the iron filling has its own hard density - know what I mean?
you should read "thirsty crow" for this. ha ha ha ha
Ping ball is lighter than water so ball will floar.
there is one doubt though. Since the quantity of water isn't specified, how can we be so sure that 'one' bottle of water will be enough to take out the ball .....???
The OP put a pic of the bottle in the question, so it's not hard enough to figure out the quantity of water. Also, the pipe is narrow and one feet long. With an assumed radius of 1 cm, the cross-section area becomes approx 3.14 cm^2. Ultimately, the volume of the pipe comes out to be 94.2 cm^3 or 94 ml. The bottle will have enough water to handle the situation.
When we pour water in the metal pipe the ping -pong ball starts floating due to the archimedes's principle
just pour water and the ball will float
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If we pour the water into the metal pipe, due to Archimedes's principle, the ball starts to float and it rises on to the surface and we can pick it up easily. So, the correct answer is, The Bottle Full of Water.