Drifting particle

speed= distance over time= 9/2=4.5
velocity=change in direction/displacement/time= 5/2=2.5

Speed is the distance traveled divided by the time taken. In this case, the distance traveled is equal to the length of the path, or 9 m. To find speed, therefore:

Speed = $\frac { 9m }{ 2s } = 4.5 \frac { m }{ s }$

Velocity is a vector quantity, which means that it must have a direction. This means that the actual distance traveled doesn't matter for velocity. Only the displacement , or distance from the original point, matters. The velocity is the rate of displacement, or displacement divided by time.

The shortest distance between two points is $\sqrt { { ({ x }_{ 2 }-{ x }_{ 1 }) }^{ 2 }+{ ({ y }_{ 2 }-{ y }_{ 1 }) }^{ 2 }\quad }$

Therefore, using ${ x }_{ 1 } = 2 m$ , ${ x }_{ 2 } = 6 m$ , ${ y }_{ 1 } = 3 m$ , and ${ y }_{ 2 } = 6 m$ :

Displacement d = $\sqrt { { ({ 6 }-{ 2 }) }^{ 2 }+{ ({ 6 }-{ 3 }) }^{ 2 } }$ = $\sqrt { { 16+9 } }$ = $\sqrt { { 25} }$ = $5 m$

Velocity = $\frac {Displacement}{Time}$

Velocity = $\frac {5m}{2s}$ = $2.5 \frac {m}{s}$

speed= distance over time= 9/2=4.5 velocity=change in direction/displacement/time= 5/2=2.5 easy solution... cheers!!!!!!!!!