Driving Word Problem

We can use the formula $distance=speed \times time$ or $d=Vt$ . The time travelled by Mrs. Hugo is 4 hours. The time travelled by Mrs. Thompson is also 4 hours. The distance travelled by Mrs. Hugo plus the distance travelled by Mrs. Thompson is equal to 452 miles. Letting $V_T$ be the speed of Mrs. Thompson and $V_H$ be the speed of Mrs. Hugo, we have the equation

$4V_H+4V_T=452$

or

$V_H+V_T=113$

Since Mrs. Hugo is 3mph faster than Mrs. Thompson, we have

$3+V_T+V_T=113$

Simplifying, we get

$V_T=\boxed{55~mph}$

This is a word problem.it is not easy, or hard. I suck at math, and I did it. The best way is to translate it into an equation, then solve. and the equation is: Mrs. Hugo's difference + Mrs. Thompson's difference has to equal 452. and distance = speed multiplied by time.

Let Mrs.Thompson's speed = X mph

This means, Mr.Hugo's speed = X +3 mph

Total speed together (in mph) = 2X + 3 mph

Total time = 4h

Total distance apart = 452 miles

Total speed in 4h = 2X + 3 mph x 4

                                                = 8X + 12 mph

Equation:

8X + 12 = 452

8X = 440

X = 55

Therefore , Mrs.Thompson's speed = 55 mph