Drop by Drop

Classical Mechanics Level 2

Water drop falls at regular intervals from a roof. At an instant when a drop is about to leave the roof, the separations between 3 successive drops below the roof are in the ratio-

1:5:13 1:3:5 1:4:5 1:2:3

Harsh Shah by Harsh Shah , 20, India

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2 solutions

Anshul Yadav
Aug 1, 2014

It is a direct use of "Galileo's law of odd numbers". Refer NCERT text book class XI part 1 page number 50.

10 Helpful 0 Interesting 0 Brilliant 0 Confused
Vinayak P
Aug 1, 2014

the time interval be 't'. the drops are numbered first, second, and last. Here the last drop is the drop which is about to leave the roof. Now, distance travelled by the first drop =1/2g(3t)^2 since u =0 and a=g and t=3t. distance travelled by second drop= 1/2g(2t)^2 distance travelled by third drop= 1/2gt^2

Ratio of separation below the roof = distance travelled by last drop: (Distance travelled by second drop - Distance travelled by last drop) : (Distance travelled by first drop - distance travelled by second drop )

1/2gt^2 : (4 * 1/2gt^2 - 1/2gt^2): (9 * 1/2gt^2 - 4 * 1/2gt^2)

ie, 1 : 3 : 5

6 Helpful 0 Interesting 0 Brilliant 0 Confused

very poorly worded question.

Hugh Kay - 6 years, 10 months ago

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