Drop The Cubes

An increasing sequence 2, 3, 4, 5, 6, 7, 9, 10, 11, 12, ... contains all positive integers which are not perfect cubes. What is the 2016th number of the sequence?


The answer is 2028.

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1 solution

Abhay Tiwari
Jun 5, 2016

The closest cube to 2016 2016 is 12 × 12 × 12 = 1728 12×12×12=1728 , so, 2016 + 12 = 2028 2016+12=\boxed{2028}

Sinple and nice(+1)

Ashish Menon - 5 years ago

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Thank you Ashish :)

Abhay Tiwari - 5 years ago

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