I drop a stone down a vertical shaft, and I hear the stone hit the bottom after 11.4 seconds. Assuming the stone accelerates at 9.8m/s/s and the speed of sound is 350m/s, how deep is the shaft in meters?
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Let t be the time it takes for the stone to hit the bottom, and s be the time it takes for the sound to reach you after it hits the bottom. Solve this system of equations: 4 . 9 t 2 = 3 5 0 s t + s = 1 1 . 4 The possible solutions are t = − 8 1 . 4 and t = 1 0 . Time obviously isn't negative here so t = 1 0 and 4 . 9 t 2 = 4 9 0 m