A boy drops a stone from the edge of a cliff such that it plops into a lake to test the height of the cliff. If he heard the sound after 3 seconds of him dropping the stone, how high is the cliff?
Note: here the speed of sound is 300m/s.
Take g=10
Put your answer in metres.*
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Here is a different method that avoids the second-degree equation. (It doesn't pay much in this case, but it can be very useful when the resulting equation is not easy to solve):
Estimate the height neglecting the time the sound needs to travel up: h = 2 1 1 0 ⋅ 3 2 = 4 5 m
Use this height to estimate the time the sound needs to travel up: t s o u n d = 3 0 0 4 5 = 0 . 1 5 s
Correct the fall time and calculate the height again: h = 2 1 1 0 ⋅ 2 . 8 5 2 = 4 0 . 6 m ≈ 4 1 m
Repeat these steps to gain precision if you wish.
What is the condition for this method to work efficiently in this case?