Dynamic Geometry: P2

Geometry Level 2

The diagram shows a blue parabola y = a x 2 + a y=ax^{2}+a and a black point P ( a ; y p ) P(a;y_{p}) with 0 a 1 0\le a\le 1 . As a a varies from 0 0 to 1 1 and back from 1 1 to 0 0 , the black point moves along a pink curve. The black angle between the two green lines is a right angle. The area bounded by the pink curve and the green lines can be expressed as b c \frac{b}{c} , where b b , and c c are coprime positive integers. Find b + c b+c .


The answer is 7.

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1 solution

K T
Feb 1, 2021

P = ( a , a x 2 + a ) P=(a, ax^2+a) . Since a = x a=x , the pink curve is given by y = x 3 + x y=x^3+x , and the area under the pink curve is A = 0 1 ( x 3 + x ) d x = 1 4 + 1 2 = 3 4 A=\int_0^1 (x^3+x) dx = \frac{1}{4}+\frac{1}{2}=\frac{3}{4}

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