If x − y = x y and x 1 + y 1 = 5 , then what is y 1 ?
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Nice - I thought the symmetry of this problem might generate some elegant solutions. Well done!
Given
1) x − y = x y
2) 1 / x + 1 / y = 5
From 2),
( x + y ) / x y = 5
with 1)
x + y = 5 x y = 5 ( x − y ) = 5 x − 5 y
6 y = 4 x
y = 2 x / 3
Substituting into 1)
x − ( 2 x / 3 ) = x ( 2 x / 3 )
Since x = 0,
1 − 2 / 3 = 2 x / 3
3 − 2 = 2 x
x = 1 / 2
y = 2 ( 1 / 2 ) / 3 = 1 / 3
1 / y = 3
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As x , y = 0 , divide the first equation through by x y to find that y 1 − x 1 = 1 . Add this to the second equation to find that
( y 1 − x 1 ) + ( x 1 + y 1 ) = 1 + 5 ⟹ y 2 = 6 ⟹ y 1 = 3 .