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Algebra Level 2

1st.case → x 2 = 9 x^{2}= \color{#3D99F6}{9}

2nd.case → x = 9 x= \color{#D61F06}{\sqrt{\color{#3D99F6}{9}}}

Note→ First value of x x in option represent the value of x x in 1st case and and in the same option second value represent the value of 2nd case.

Inspiration

x= + 3 +3 , − 3 -3 x= − 3 -3 , ± 3 \pm3 x= ± 3 \pm3 , + 3 +3 x= ± 3 \pm3 , − 3 -3 x= ± 3 \pm3 , ± 3 \pm3 x= − 3 -3 , + 3 +3 x= + 3 +3 , ± 3 \pm3

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1 solution

Jolly Ghosh
Oct 23, 2015

For the first case,

x^2 = 9 => x = (9)^(1/2), i.e. {+3,-3} since powering with halves provide all the values of the number.

For the second case,

Consider the definition of surds which tells that under-roots must always return a positive value. This implies x = √9 must definitely be equal to +3.

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