A geometry problem by Mohammad Khaza

Geometry Level 1

Find the length of the longest pole that can be placed in a room $5m$ long, $4m$ broad and $3m$ high.

6.9 7.05 5.2 8.65

1 solution

Mohammad Khaza
Aug 4, 2017

length of longest pole=length of diagonal= $\sqrt{(5^2+4^2+3^2)}$ = $√50=7.05$

You can try \sqrt{(5^2 + 4^2 + 3^2)}

which appears as $\sqrt{(5^2 + 4^2 + 3^2)}$

Munem Shahriar - 3 years, 9 months ago

thank you very much.

Mohammad Khaza - 3 years, 9 months ago

The the most accurate answer is $\sqrt{50}=5\sqrt{2} \approx 7.07$ .

A Former Brilliant Member - 3 years, 3 months ago

yes.you are correct.

Mohammad Khaza - 3 years, 3 months ago