Deceptive Differentiation

Calculus Level 4

Derivative of $\text{f(x)}$ with respect to $y$ of

$\text{f(x)} = x^x$

e^x

x^x (\ln(x)-1)

x^x

x^x (\ln(x) + 1)

1 solution

Curtis Clement
Sep 16, 2015

We are differentiating with a different variable so the derivative is always zero not matter what f(x) is defined as

Why can't I take $y=f(x)$ ? I had a confusion

Hjalmar Orellana Soto - 5 years, 8 months ago

Well, no.

Note that f(x) can be any variable a,b,c,d,....z unless until we specify that specifically. Here, f(x) is just taken as f(x).

Pulkit Gupta - 5 years, 4 months ago

But we won't consider $x$ to be a constant with respect to $y$

Ankit Kumar Jain - 4 years, 1 month ago

This shouldn't be a level 4 problem

Sanjoy Kundu - 3 years, 10 months ago

Please help me out with it.How is the derivative wrt y = 0?

Ankit Kumar Jain - 3 years, 10 months ago

Because x is treated as a constant, and the derivative of a constant is 0.

Sanjoy Kundu - 3 years, 10 months ago

As the name says..... Deceptive

Sarthak Shiv - 3 years, 8 months ago