Easy

Good question! every divisor can be written be form $2^7*3^3*5^2$ so every divisor can be arranged as $\Rightarrow \frac{2^7*3^3*5^2}{d} = n=\frac{2^7*3^3*5^2}{2^p*3^q*5^r}$

thus, $d=2^p*3^q*5^r$ Remember that any nonzero number raised to the zeroth power equals 1. So p, q and r can also be 0. So p can be 0, 1, 2, 3, 4, 5, 6 or 7 which gives for 8 possibilities for p. q can be 0,1,2 or 3, which gives 4 possibilities for q.Same for r. The number of possibilities is just one larger than the corresponding exponent.Thus,every power(th) term must be added then multiplied. $\rightarrow (8)(4)(3)$