What about it?

If A = 123456789 A=123456789 and B = 987654321 B=987654321 , what are the last two digits of A × B A\times B ?


The answer is 69.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Finn C
May 18, 2016

If you want to simplify Sam Bealing's solution further, instead of multiplying 2 digit numbers you can do:

9 x 1 = 9 (our last digit)

and

2 x 8 = 16, although we only take the 6

Therefore, our answer is 69

Nice, didn't think of that. Though you may want to point out that it only works since 9x1 is less than 10

Alex Li - 4 years, 9 months ago
Sam Bealing
May 10, 2016

We need only multiply the last two digits of each number to find the last two digits of A × B A \times B :

21 × 89 = 1869 21 \times 89=1869

The last two digits are therfore:

69 \boxed{69}

Nice solution

Fidel Simanjuntak - 5 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...