EASY ALGEBRA

Calculus Level 3

The minimum value of the polynomial p ( x ) = 3 x 2 5 x + 2 p(x) =3x^2-5x+2


The answer is -0.083.

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2 solutions

The derivative of the given p ( x ) = 3 x 2 5 x + 2 p(x) = 3x^{2} - 5x +2 with respect to x x is 6 x 5 6x - 5 , and we know that an extrema is attained when the slope of the tangent drawn to the graph at that point is 0 0 . Hence, equating slope as a function of x x to be 0 0 , we get 6 x 5 = 0 x = 5 6 6x-5=0 \Rightarrow x = \dfrac{5}{6} . Hence, the minimum value is p ( 5 6 ) = 0.083 p(\dfrac{5}{6}) = \boxed{-0.083} .

Pranjal Jain
Jan 8, 2015

Differentiate polynomial wrt x,

6 x 5 = 0 x = 5 6 6x-5=0\Rightarrow x=\frac{5}{6}

Substitute x to calculate minima which comes out to be 1 12 = 0.082 \frac{-1}{12}=-0.082


@Gogul Raman Thirunathan I have fixed LaTeX in your question. Please make sure I have not altered question in any way. You may use it as reference later. Click edit to view LaTeX.

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