A calculus problem by Shivam Jadhav

Calculus Level 4

If a 1 , a 2 , a 3 , . . . . . . . . , a n a_{1},a_{2},a_{3},........,a_{n} is a sequence of positive numbers which are in A.P with common difference 'd' and a 1 + a 4 + a 7 + . . . . . . . + a 16 = 147 a_{1}+a_{4}+a_{7}+.......+a_{16}=147 , then a 1 + a 16 = M a_{1}+a_{16}=M a 1 + a 6 + a 11 + a 16 = N a_{1}+a_{6}+a_{11}+a_{16}=N Maximum value of a 1 a 2 . . . . . . a 16 = ( S W ) 16 a_{1}a_{2}......a_{16}=(\frac{S}{W})^{16} here S and W are co-prime non-negative integers. Find S + W + M + N S+W+M+N


The answer is 198.

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1 solution

Shivam Jadhav
Apr 17, 2015

Use A . M G . M A.M-G.M inequality to find S and W. We can find M and N by manipulation. M=49 , N=98 , S =49 , W =2 Therefore M+N+S+W = 198

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