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x 9 + x 8 − x 7 + x 6 − x 5 + x 4 − x 3 + x + 1 = 0 How many real roots are there?
The answer is 1.
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1 solution
can you write the solution
Pls write the solution
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I haven't used pen or paper to solve this,as I knew that for some odd degree equation their is only one real roots and remaining are imaginary
But I will try to get the solution of it
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I believe that you mean for an odd degree equation there is at LEAST one real root, due to an odd degree function having extrema at negative infinity and positive infinity.
There are infinitely many odd degree polynomials with more than one real root. Take f ( x ) = x 3 − x for example. It has real roots x = − 1 , 0 , 1 .
Your reply to my other solution was correct. For some reason I thought that the equation had only pluses instead of some pluses and some minuses.
I did not understand. Please elaborate!
Since it is an equation of odd power hence only one real root will be their and others will be imaginary