Happy new functions 2018!!

Geometry Level 4

For any positive integer n n , define f n : ( 0 , ) R f_n : (0, \infty) \rightarrow \mathbb R as

f n ( x ) = j = 1 n tan 1 ( 1 1 + ( x + j ) ( x + j 1 ) ) x ( 0 , ) \large\ { f }_{ n }\left( x \right) = \displaystyle \sum _{ j=1 }^{ n }{ \tan ^{ -1 }{ \left( \frac { 1 }{ 1 + \left( x + j \right) \left( x + j - 1 \right) } \right) } } \forall x \in \left( 0, \infty \right) .

Find the value of

j = 1 5 tan 2 ( f j ( 0 ) ) \large\ \sum _{ j=1 }^{ 5 }{ \tan ^{ 2 }{ \left( { f }_{ j }\left( 0 \right) \right) } } .


The answer is 55.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Suhas Sheikh
Jun 2, 2018

The question is an advanced 2018 ripoff But do note That 0 is not in the domain of definition of the function F(x) As such evaluation of f_j(0) becomes invalid

so the ans wont be 55.. :(.... I marked it...... -_-.

rajdeep brahma - 3 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...