Confusing

Calculus Level 2

X=COSt y=sin^2 t then what is d^2 y/ dx^2


The answer is -2.

Rithik Sharma by Rithik Sharma , 22, India

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2 solutions

y = sin ⁡ 2 t = 1 − cos ⁡ 2 t = 1 − x 2 y=\sin^2 {t} = 1-\cos^2{t} = 1 -x^2

⇒ d y d x = − 2 x ⇒ d 2 y d x 2 = − 2 \Rightarrow \dfrac {dy}{dx} = -2x\quad \Rightarrow \dfrac {d^2y}{dx^2} = \boxed{-2}

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Rithik Sharma
Mar 29, 2015

y=sin^2 t
y=1-cos^2 t
y = 1 - x^2 dy/dx= -2 x
d^2 y/dx^2 = -2


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You should learn up how to use LaTex.

Chew-Seong Cheong - 6 years, 2 months ago

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