This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
this is unnecessary, because you know that the product of the last digits of the two numbers is 63-54=9
yep used bodmas
I forgot to subtract :(
By multiplying 9 of 689 with 7 of 367 expected unit digit will be 3,while subtracting 4 of 54 left over digit will be 9 Ans.
K.K.GARG,India
How 1 we hav to subtract then product ???
i used the BODMAS and solved the question
To the modulus 10: 9*7-4=3-4=9. With congruencies, which I don't know how to type.
Let's take a simple approach:
The last digit of 9 × 7 is 3 . The last digit of 3 − 4 is 9 , due to the fact that the quantity 6 8 9 is positive.
Thus, the last digit of the value of the expression is equal to 9 .
9x7=63....last digit is 3 ....using it to minus 4 unit digit in 54 is impossible, so you need to borrow 10 which means 10+3-4=9
There is no need to use BODMAS. Just multiply the unit place digits i.e 9 and 7 = 63 therefore , the units digit of the product will be 3. Now if we have to subtract 4 ( units digit of 54 ) from the product. We will use the simple carry-over property, therefore the unit's digit will be 13-4 = 9
Since the question is only searching for the unit digit, we can just use the numbers in the unit position (9, 7, and 4, in that order) thus 9 * 7 = 63, then 63 - 4 = 9. Simple as that.
Problem Loading...
Note Loading...
Set Loading...
using bodmas (braket of division multiplication addition substraction) first multiply 689*367 then subtract 57 from that product we get 252809 here 9 is in units place.