Easy but surely pleasant ...!!
An object is thrown from a height of 200 m and simultaneously one other stone is projected upwards with a velocity of 50 m per second .
[Take g as 10 ]
Find the height where they meet . (Height is measured from the ground)
Find also the time after which the two stones meet .
Enter the answer as how close the projected stone move towards the meeting point per second.
I mean - Height/time
The answer is 20.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
0 solutions
No explanations have been posted yet. Check back later!