Easy Complex question (part-1)

A ladder of length l and uniform mass density stands on a frictionless floor and leans against a frictionless wall. It is initially held motionless, with its bottom end an infinitesimal distance from the wall. It is then released, whereupon the bottom end slides away from the wall, and the top end slides down the wall. When it loses contact with the wall, what is the horizontal component of the velocity of the center of mass? Note l = 10m Take g = 10 m/ s 2 s^{2}


The answer is 3.333.

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1 solution

Ahmed Aljayashi
Jul 21, 2019

I did it by the usual Newtonian way , but it can easily be done throughout Lagrangian formulation.

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