x
=
y
+
1
y
−
1
Express
y
in terms of
x
.
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As @Kislay Raj said, Componendo et Divideno is the best approach to this problem.
x = y + 1 y − 1 ⟹ 1 x 2 = y + 1 y − 1 ⟹ x 2 − 1 x 2 + 1 = y − 1 − y − 1 y − 1 + y + 1 ⟹ y = 1 − x 2 1 + x 2
you could have applied Componendo & Dividendo to shorten the soln (just around 2 steps).
i dont understand 2nd last step?? :(
x x 2 x 2 x 2 x 2 x 2 − 1 y + 1 2 1 − x 2 2 1 − x 2 2 − 1 1 − x 2 2 − 1 − x 2 1 − x 2 1 − x 2 2 − ( 1 − x 2 ) 1 − x 2 1 + x 2 = y + 1 y − 1 = y + 1 y − 1 = y + 1 y + 1 − 2 = y + 1 y + 1 − y + 1 2 = 1 − y + 1 2 = − y + 1 2 = 1 − x 2 = y + 1 = y = y = y = y
Thats really nice
x x 2 ( y + 1 ) x 2 x 2 y + x 2 y − x 2 y y ( 1 − x 2 ) y = = = = = = = y + 1 y − 1 y + 1 y − 1 y − 1 y − 1 1 + x 2 1 + x 2 1 − x 2 1 + x 2
First square both sides. Then the equation will be, x^2 = y - 1 / y + 1.
x^2 + 1 / x^2 - 1 = y - 1 + y + 1 / y - 1-y - 1. [Componendo - Dividendo].
y = 1 + x^2/1 - x^2
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x = y + 1 y − 1 ⟺ x 2 = y + 1 y − 1 ⟺ ( y + 1 ) x 2 = y − 1 ⟺ y x 2 + x 2 = y − 1 ⟺ y x 2 − y = − ( x 2 + 1 ) ⟺ y ( x 2 − 1 ) = − ( x 2 + 1 ) ⟺ y = − 1 − 1 ⋅ 1 − x 2 x 2 + 1 ⟺ y = 1 − x 2 x 2 + 1