Easy Floors.

Algebra Level 5

x 101 = x 100 \left\lfloor \frac { x }{ 101 } \right\rfloor =\left\lfloor \frac { x }{ 100 } \right\rfloor

Find the number of non-negative integer solutions of the above equation.


The answer is 5050.

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2 solutions

Rohit Sachdeva
Apr 17, 2015

0-99 will give floor value 0 for both

101-199 will give floor value 1 for both

202-299 will give floor value 2 for both

....... & so on till 9999-9999 which gives floor value 99 for both

After this no number gives same floor value for both (x/101) & (x/100)

So number of values for x:

100+99+98+......1=5050

Did the same !! (+1)

Akshat Sharda - 5 years, 4 months ago
William Isoroku
Jan 25, 2016

No need for complicated algebra or inequalities, just observe and the answer will come! The possible values of x x are as follows:

0 < x < 100 0<x<100 100 possible values

100 < x < 200 100<x<200 99 values

201 < x < 300 201<x<300 98 values

302 < x < 400 302<x<400 97 values

403 < x < 500 403<x<500 96 values....

Clearly the possibilities are in arithmetic series and that's no surprise; the lower extreme of the inequalities above needs to be 1 1 less than the multiples of 101 101 .

Summing it up: 100 + 99 + 98 + 97 + . . . . + 2 + 1 = 5050 100+99+98+97+....+2+1=5050

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