Easy functional equation

Algebra Level 2

A function f f satisfies f ( x ) + f ( 3 x ) = x 2 + 1 f(x)+f(3x)=x^2+1 for all real numbers x x .

If f ( 2 ) + f ( 18 ) = 6 f(2)+f(18)=6 , determine the value of f ( 6 ) f(6) .


This is a part of the Set .


The answer is 18.

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2 solutions

For x = 2 x=2 , f ( 2 ) + f ( 6 ) = 5 ( 1 ) f(2)+f(6)=5\qquad(1) .

For x = 6 x=6 , f ( 6 ) + f ( 18 ) = 37 ( 2 ) f(6)+f(18)=37\qquad(2) .

From ( 1 ) (1) and ( 2 ) (2) , we have f ( 2 ) + f ( 18 ) + 2 f ( 6 ) = 42 f(2)+f(18)+2f(6)=42 or 2 f ( 6 ) + 6 = 42 2f(6)+6=42 .

So, f ( 6 ) = 18 f(6)=\boxed{18} .

Bill Bell
Oct 8, 2015

Same method as for the first answerer, using Sage.

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