Easy Integer
Algebra
Level
4
Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the third integers.
The answer is 11.
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1 solution
First integer = x
Second integer = x + 2
Third integer = x + 4
Since four times the first integer equals six more than the product of two and the third integer.
=> 4x = 6 + 2(x + 4)
=> 4x = 6 + 2x + 8
=> 2x = 14
=> x = 7.
Hence,
First integer = x = 7
Second integer = x + 2 = 7 + 2 = 9
Third integer = x + 4 = 7 + 4 = 11.