If sin − 1 x + sin − 1 y + sin − 1 z = 2 3 π , then
arcsin ( 2 0 1 5 x 2 0 1 5 − 2 0 1 7 x 2 0 1 7 2 0 1 7 x 2 0 1 7 − 2 0 1 6 x 2 0 1 6 ) = b a π
where a and b are coprime integers. Find ∣ a + b ∣ .
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(pi/2) is the maximum value of arcsin(x), arcsin(y) & arcsin(z). So easily x=y=z=1. Now the asked value is arcsin(-1/2) so it is (-pi/6).
PS: The question must be edited because someone could consider denominator as negative so answer can also be -5