A calculus problem by Sharad Roy

Calculus Level 2

F i n d t h e v a l u e o f 0 10 6 + 6 + 6 + 6 + . . . . . . . d x Find\quad the\quad value\quad of\quad \\ \\ \int _{ 0 }^{ 10 }{ \sqrt { 6+\sqrt { 6+\sqrt { 6+\sqrt { 6+.......\infty } } } } } dx


The answer is 30.

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1 solution

L N
Jun 6, 2014

Let S = 6 + 6... S = \sqrt{6 + \sqrt{6 ... } } Then, S = 6 + S S = \sqrt{6+S} . Simplify: S 2 = S + 6 S^2 = S + 6 , S 2 S 6 = 0 S^2 - S - 6 = 0 , ( S + 2 ) ( S 3 ) = 0 (S+2)(S-3) = 0 , Clearly S S cannot be negative, therefore, S = 3 S = 3 , Now, 0 10 3 = 3 ( 10 ) 0 = 30 \int_{0}^{10} 3 = 3(10)-0 = 30

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