Easy layover

The greatest common divisor is equal to the product of the lowest power of each prime. In this case, that is $2^1\cdot 3^0\cdot 5^1\cdot 7^0=\boxed{10}$ .

Firstly, you need to know the definition of GCD it means greatest common divisor. Secondly, you must take the numbers they share in this case it is 2 and 5 then multiply them. Finally, the answer appears. 10!

as multliplication of 2x3x5 n 2x5x7 is 30 n 70 respetively so their is 10

2 x 3 x 5 = 30

2 x 5 x 7 = 70

Both can be divided by 10

To find out the GCD between two numbers, we first need to write them as prime factors. Now we see that this has been done for us: 2, 3, 5 and 7 are all prime numbers. The GCD of two positive integers is simply the product of all the prime factors they have in common. 2 is in both the numbers, 5 as well. Thus, the answer is the product of 2 and 5, which is $2 \times 5 = \fbox{10}$

The two numbers are split into their individual prime factors. It is therefore easy to find out their greatest common divisor. Since both of them have 2 and 5 as factors, and \frac {7}{3} =/= an integer, therefore the greatest common divisor is 2 \times 5=10.

Compare 2^1 x 3^1 x 5^1 x 7^0 and 2^1 x 3^0 x 5^1 x 7^1 . Take the smallest num of degree and take their product. In this case: 2^1 x 3^0 x 5^1 x 7^0 = 10

the most number is 2 and 5. So, you just 2x5 = 10

THERE IS COMMON 2& 5 SO 2.5= 10

The greatest common divisor is always the product of the common numbers that appear in both of the prime factorisation.

2 * 3 * 5 , 2 * 5 * 7

They both have 2 and 5

x = 2 * 5 = 10

10

You multiply the three numbers together for each equation. eg. 2x3x5= 30 2x5x7=70 Common factors of each equation: 2, 5, 10 HCF: 10 Highest common divisor = 10

2 3 5 and 2 5 7,there is 2*5 is common which is 10 and also it is the greatest divisor..thus, 10 is the GCD of these priducts

3 and 7 are non-common factors ....so gcd is 5*2 that is 10

just look at the same nubers => 2 & 5 so 2x5= 10