Easy Math Problem 2

For any finite $n$ , $n \times 0 = 0$ . Since the number inside the brackets is finite(because it doesn't contain $\infty$ ), the answer is $0$ .

$0\left(6\left(\frac{6}{6}\right) + 0\right) = 0(6(1) + 0) = 0(6 + 0) = 0(6) = \green{\boxed{0}}$

$\frac{6}{6} = 1$

$6 \times 1 = 6$

$6 + 0 = 6$

$6 \times 0 = 0$