I need to graph this

Using calculus, let $f(x) = sin(x) + 9csc(x)$ and $f'(x) = cos(x) - 9csc(x)cot(x) = 0$ . This first derivative is then simplified according to:

$cos(x) = 9 csc(x)cot(x) \Rightarrow cos(x) = \frac{9cos(x)}{sin^{2}(x)} \Rightarrow sin^{2}(x) = 9 \Rightarrow sin(x) = \pm 3$

which is impossible for $x \in \mathbb{R}$ .