Easy NT!

If (p,q) satisfy the condition that p divides ${q}^{2}-4$ and q divides ${p}^{2}-1$ , then find the sum of all such primes.

Details

If the ordered pair of such primes are $({p}_{1}, {q}_{1}), ({p}_{2},{q}_{2}),.... ({p}_{n}, {q}_{n})$ , then give your answer as ${p}_{1} + {q}_{1} + {p}_{2} + {q}_{2}+ .... +{p}_{n} + {q}_{n}$