A number theory problem by s p

Let S S be the set of all integers n n such that 8 n 3 96 n 2 + 360 n 400 2 n 7 \dfrac{8n^3-96n^2+360n-400}{2n-7} is an integer . Find the value of n S n \displaystyle \sum_{n\in S} |n|


The answer is 50.

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1 solution

Andrey Pershin
Aug 9, 2018

Remainder of this fraction is 27, so if we need to get integer number, the denominator of fraction 27 2 n 7 \frac{27}{2n-7} must be equal ± 1 \pm1 , ± 3 \pm3 , ± 9 \pm9 or ± 27 \pm27 . Possible values of n is n = 10 , 1 , 2 , 3 , 4 , 5 , 8 , 17 n=-10{,}-1{,}2{,}3{,}4{,}5{,}8{,}17 . As a result the sum of absolute values is \sum_{n} \vert n \vert\=50

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