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1 solution
cos2theta=(cos^2)theta-(sin^2)theta-------------1. ALSO,
sin2theta=2sin theta*cos theta-----------------2.
now, cross multiplying (cos theta)/p=(sin theta)/q we get (cos theta) q=(sin theta) p
now we convert sec2theta and cossec2theta in the form of given equations above 1and 2 and hence get p as answer.