Easy or Troll

A car have 100 people inside, 40 of them are women and 60 men, men weights 1.22234 times women and they are identical therefore excluding any other random weights, If there is wind of 50N opposing car which moves with 3.4 ms^{2} then what is the total force applied by car?

  • Gravity and g-force is constant.
  • Men are heavier. -There is no children inside or perhaps the same size.
  • Wind is constant.
  • Road and tyre conditions are good.
  • Gravity is thirty Newton.
  • They are not Eating or Drinking.
  • No hard or soft chairs inside a car.
  • Everyone is relaxed and Calm.
  • Women weights five hundred kilograms.

Good Luck!

29.900 37.092 0 75.555 75.933 75.041

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1 solution

Syed Baqir
Apr 14, 2016

Total weight = ( 500 + 1.22234 500 ) 30 \frac{(500+1.22234*500)}{30} = 37.039 = \ 37.039
F=ma

\therefore
37.039*3.4=125.9326

AS there is wind

125.9326 - 50 =75.9326

@Syed Baqir Why divided by 30 ?

My answer comes out to be 37 N

Saraswati Sharma - 4 years, 7 months ago

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