problems #1

we find that the triangle is right angled. so the hypotenuse will become the diameter. therefore circumradius = 29/2 area of circle = pi * r^2. so x = r^2 x = 841/4 = 210.25

ABC is a right triangle by the Pythagorean Theorem. Since that is the case, CA will be the diameter of the circumcircle of ABC, hence, the radius is \frac { 29 }{ 2 } , area is { \left( \frac { 29 }{ 2 } \right) }^{ 2 }\pi \quad units\quad =\quad \boxed { 210.25 } \pi \quad units.

$x\pi$ = $\pi \cdot r^2$

Where $r$ is the circumradius.

So $x$ = $r^2$

And $r$ = $abc / 4area$

By calculation $x$ = 210.25