Easy Question

$2014!\times2015!$ ,

= $5\times2$

=10

The answer comes 10 and its last digit is 0.

The last digit of $2014!$ is 0, and the last digit of $2015!$ is 0, thus the last digit of $2014! \times 2015!$ is 0.

Because they have a common factor, 2, and 5.

Trick Question: Any $n!$ for $n\geq{5}$ and an integer has 1 or more trailing zeros, so the answer is just $\boxed{0}$ .

In $2014!\times2015!$ , $5\times2=10$ also comes and anything times 10 will have its last digit 0 so last digit is $\boxed{0}$

In $2014! \times 2015!$ , $5 \times 2$ will also come that is equal to 10 and if ten is multiplied with any number then its last digit is zero .