easy series....

The $n^{th}$ term $a_n$ is given by $a_n=n^n-n$ . Therefore, for $n=5$ , $a_5=5^5-5=3125-5=\boxed{3120}$ .

The nth term is n^n-n. 1^1-1=0 2^2-2=2 ....... ....... 5^5-5=3120