Easy SHM!
A Particle performing Simple harmonic motion undergoes initial displacement of (Where Is amplitude of SHM) in 1 second. at t=0 the particle may be at extreme or mean position.the time period of the simple harmonic motion can be
A) 6 second
B) 2.4 second
C) 12 Second
D) 1.2 second
For the problem writing party
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1 solution
For extreme position,
x = x m c o s ( ω t ) so if x = x m / 2 then c o s ( ω t ) = 1 / 2 giving ω t = π / 3 hence t = T / 6 .
For mean position,
x = x m s i n ( ω t ) so if x = x m / 2 then s i n ( ω t ) = 1 / 2 giving ω t = π / 6 hence t = T / 1 2 .
Therefore since t = 1 s T can be 6 or 1 2 seconds.