⎩ ⎨ ⎧ x y = 1 2 x + y = 7
There are two ( x , y ) pairs satisfying the the system of equations above. Find the product x 1 x 2 y 1 y 2 .
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Very simple.
x ⋅ y = 1 2
x 1 × x 2 × y 1 × y 2 = 1 2 × 1 2 = 1 4 4
3,4&&4,3 Product is 12²=144
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(X1)(Y1)=12, (X2)(Y2)=12. Thus, (X1)(Y1)(X2)(Y2)=144