Sine and Cosine

Geometry Level 1

If sin ( x ) + cos ( y ) = 2 \sin(x)+\cos(y)=2 , determine the value of x + y x+y in degrees, for 0 x 36 0 0^\circ \le x \le 360^\circ and 0 y < 36 0 0^\circ \le y < 360^\circ .


The answer is 90.

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1 solution

Yashas Ravi
Mar 22, 2019

Since the maximum value of sin ( a ) \sin(a) or cos ( a ) \cos(a) for any real a a is 1 1 , then the maximum value of sin ( x ) \sin(x) and cos ( y ) \cos(y) are both 1 1 . As a result, the maximum value of sin ( x ) + cos ( y ) = 2 \sin(x)+\cos(y)=2 . This only happens when x = 90 x=90 and y = 0 y=0 , since sin ( 90 ) = 1 \sin(90)=1 and cos ( 0 ) = 1 \cos(0)=1 . As a result, ( x + y ) = 0 + 90 = 90 (x+y)=0+90=90 .

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