Easy Symmetry

Alpha, Beta, Gamma, Delta play a game where they will each point at someone else at random at the same time. Whichever player has the most fingers pointed at them will be eliminated. In the case of a tie they will rerun the round. The game ends when 2 players are left in the game and they are considered the winners. What is the probability that Gamma is not a winner?


The answer is 0.5.

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1 solution

Ephram Chun
Jan 26, 2021

We can see that this game is random thus every single player has an equal chance at winning or losing. Thus there is ( 4 2 ) = 6 \binom{4}{2}=6 ways for the winners to be decided and since Gamma is not a winner in 3 of the ways our answer is 1 2 \boxed{\frac{1}{2}} .

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