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Find sin ⁡ 2 4 9 o + sin ⁡ 2 4 1 o \sin^2 \ 49^o + \sin^2 41^o


The answer is 1.

Nilotpal Chakraborty by Nilotpal Chakraborty , 21, India

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1 solution

Tom Engelsman
Mar 16, 2021

Knowing that sin ⁡ ( 4 1 o ) = cos ⁡ ( 4 9 o ) \sin(41^{o}) = \cos(49^{o}) , we have sin ⁡ 2 ( 4 9 o ) + cos ⁡ 2 ( 4 9 o ) = 1 . \sin^{2}(49^{o}) + \cos^{2}(49^{o}) = \boxed{1}.

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